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inπ

e^(lnπ)=e^(loge π)=π这里有个公式:a^(loga b)=b 推导过程: 假设 a^c = b 那么loga b = c,代入上式 ∴ a^(loga b)=b 很乐意帮助你哦!有什么问题尽管问 O(∩_∩)O

Inπ≈1.14473 不懂可追问 有帮助请采纳 祝你学习进步 谢谢

4sinπ/10 *cosπ/5=4sinπ/10 *cosπ/10 *cosπ/5 /(cosπ/10) 由公式sin2a=2sina*cosa可以知道,4sinπ/10 *cosπ/10 *cosπ/5=2sinπ/5*cosπ/5=sin 2π/5=cos(π/2 -2π/5)=cos π/10所以4sinπ/10 *cosπ/5=4sin

4sin π/4 cos π/4=2乘2sin π/4 cos π/4=2sin π/2 =2sin90度=2乘1=2不懂的欢迎追问,

e^(iπ)=-1e^(inπ)=(-1)^n

考查行列式运算法则.cosπ3sinπ6sinπ3cosπ6.=cosπ3cosπ6-sinπ3sinπ6=12*3232*12=0.故答案为:0

cosπ/4cosπ/3-sinπ/4sinπ/3=cos45°cos60°-sin45°sin60°=(√2/2)*(1/2)- (√2/2)*(√3/2)=(√2-√6)/4

4sinπ/24cosπ/24cosπ/12=2sinπ/12cosπ/12=sinπ/6=1/2

sin π/3tan π/6+ π/4sin π/4=二分之根号三 * 三分之根号三 + π/4*二分之根号2=(根号2*π+4)/8我打不出根号

cosπ/5cos2π/5=2sinπ/5cosπ/5cos2π/5/(2sinπ/5)=sin2π/5cos2π/5/(2sinπ/5)=2sin2π/5cos2π/5/(4sinπ/5)=sin4π/5/(4sinπ/5)=sin(π-π/5)/(4sinπ/5)=sinπ/5/(4sinπ/5)=1/4 没有什么特殊公式

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